Web3. The center of the mirror is given by C = 2 f. Thus, the object is located beyond the center of the mirror. According to ray diagrams you expect that the image is located between C … Web1 sep. 2024 · Light Reflection and Refraction HOTS Questions With Answers. Question 1. The refractive indices of water and glass with respect to air are 4/3 and 3/2 respectively. …
Mirror Equation - Formula, Sign conventions, …
Web13. An arrow 2.5 cm high is placed at a distance of 25 cm from a diverging mirror of focal length 20 cm. Find the nature, position and size of the image formed. 14. A convex … Web3 aug. 2024 · Write down the relation between the focal length (f) and radius of curvature (R) of a spherical mirror. Answer: f = R/2. Question 17. Name the mirror which acts as (i) a convergent mirror and (ii) divergent mirror. Answer: (i) concave mirror, (ii) … bunty aur babli 2 plot
Mirror Formula and Magnification - GeeksforGeeks
WebMirror Numericals worksheet Live worksheets > English Mirror Numericals Numericals based on mirror formula ID: 2154195 Language: English School subject: Physics Grade/level: Grade 12 Age: 15-17 Main content: Focal length, height, distance Other contents: object, image Add to my workbooks (2) Download file pdf Embed in my website … Web12 apr. 2024 · Electric Field An electric field is a vector field that describes the force exerted by a charged object on other charged objects in its vicinity. It is a fundamental concept in electromagnetism and is essential for understanding the behavior of electrically charged particles and systems. The electric field at a given point in space is … Continue reading … WebFrom lens equation v= u+fuf = −16+24−16×24=−48cm ,-ive sign shows that image will be formed on the same side of lens , where the object is placed . Now linear magnification m=I/O=v/u=−48/−16=+3 ,or I=3×4=12cm (given O=4cm) ,since m=+ive and m>1 ,therefore image will be virtual ,erect and magnified . REVISE WITH CONCEPTS hallmark christmas movies today