Filter list by another list python
WebI need to compare two lists in order to create a new list of specific elements found in one list but not in the other. For example: main_list= [] list_1= ["a", "b", "c", "d", "e"] list_2= ["a", "f", "c", "m"] I want to loop through list_1 and append to main_list all the elements from list_2 that are not found in list_1. The result should be: WebFeb 22, 2024 · A Computer Science portal for geeks. It contains well written, well thought and well explained computer science and programming articles, quizzes and practice/competitive programming/company interview Questions.
Filter list by another list python
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WebJun 22, 2012 · answered Jun 21, 2012 at 20:32. DSM. 336k 63 585 487. Add a comment. 6. I would use itertools.compress () along with a generator expression to do this: def func (a, b, c): return itertools.compress (a, (x == c for x in b)) Note that this will return a generator. If you need a list, wrap it in a list () call. WebMar 24, 2024 · Data Structures & Algorithms in Python; Explore More Self-Paced Courses; Programming Languages. C++ Programming - Beginner to Advanced; Java Programming - Beginner to Advanced; C Programming - Beginner to Advanced; Web Development. Full Stack Development with React & Node JS(Live) Java Backend Development(Live) …
WebMay 30, 2024 · filtered_list = [i for (i, v) in zip (list_a, filter) if v] Using zip is the pythonic way to iterate over multiple sequences in parallel, without needing any indexing. This assumes both sequences have the same length (zip stops after the shortest runs out). Using itertools for such a simple case is a bit overkill ... WebApr 15, 2024 · April 15, 2024. The Python filter function is a built-in way of filtering an iterable, such as a list, tuple, or dictionary, to include only items that meet a condition. In this tutorial, you’ll learn how to use the filter () function to filter items that meet a condition. You’ll learn how to use the function to filter lists, tuples, and ...
Web22 hours ago · 0. This must be a obvious one for many. But I am trying to understand how python matches a filter that is a series object passed to filter in dataframe. For eg: df is a dataframe. mask = df [column1].str.isdigit () == False ## mask is a series object with boolean values. when I do the below, are the indexes of the series (mask) matched with ... WebApr 23, 2012 · As you see the operation of masking on array is more elegant compared to list. If you try to use the array masking scheme on list you'll get an error: >>> lst [msk] Traceback (most recent call last): File "", line 1, in TypeError: only integer arrays with one element can be converted to an index.
WebPython’s filter () is a built-in function that allows you to process an iterable and extract those items that satisfy a given condition. This process is commonly known as a filtering operation. With filter (), you can apply a filtering function to an iterable and produce a new iterable with the items that satisfy the condition at hand.
WebJun 9, 2013 · 1. Check out filter and any in the python docs. >>> data_list = ['a.1','b.2','c.3'] >>> test_list = ['a.','c.'] >>> new_list = filter (lambda x: any (x.startswith (t) for t in test_list), data_list) >>> new_list ['a.1', 'c.3'] Then you can do whatever you want with the stuff in your new_list. As @Chepner points out, you can also supply a tuple ... orange cactus plantorange cadWebMar 14, 2015 · 1. Universal approach to filter the list of dictionaries based on key-value pairs. def get_dic_filter_func (**kwargs): """Func to be used for map/filter function, returned func will take dict values from kwargs keys and compare resulted dict with kwargs""" def func (dic): dic_to_compare = {k: v for k, v in dic.items () if k in kwargs} return ... iphone font for windowsWebApr 17, 2024 · The filter(function, iterable) function takes a function as input that takes on argument (a list element) and returns a Boolean value that … orange cactus remodelingWebJan 28, 2010 · Another way is to use the filter function. In Python 2: >>> filter (lambda k: 'ab' in k, lst) ['ab', 'abc'] In Python 3, it returns an iterator instead of a list, but you can cast it: >>> list (filter (lambda k: 'ab' in k, lst)) ['ab', 'abc'] Though it's better practice to use a comprehension. Share Improve this answer Follow orange cafe chingfordWebMar 17, 2024 · You could use a regular expression to pull out the part of the string you want to match and check if that is in the list. >>> import re >>> names = ['aet2000','ppt2000', 'xxx2001', 'ppt2001'] >>> wanted_list = ['aet','xxx'] >>> [name for name in names if re.match (r' [^\d]+ ^', name).group (0) in wanted_list] ['aet2000', 'xxx2001'] Share iphone food emojisWebAug 5, 2024 · Since you specifically asked about filtering the list you have, you can use filter builtin with lambda to filter out the elements from the list. >>> list (filter (lambda x: x.get ('text', '')=='abc', listpost)) [ {'post_id': '01', 'text': 'abc', 'time': datetime.datetime (2024, 8, 5, 15, 53, 19), 'type': 'normal'}] orange cafe international coffee