Balance the equation Br2 + KI = I2 + KBr using the algebraic method or linear algebra with steps. Label Each Compound With a Variable Label each compound (reactant or product) in the equation with a variable to represent the unknown coefficients. a Br2 + b KI = c I2 + d KBr Create a System of Equations WebJan 31, 2024 · Calculate the number of moles of excess reactant that will be left-over when 50.0 g of KI react with 50.0 g of Br2: 2KI + Br2 2KBr + I2 See answers Advertisement Alleei Answer : The moles of excess reactant, is, 0.1625 mole. Explanation : Given, Mass of = 50 g Mass of = 50 g Molar mass of = 166 g/mole Molar mass of = 160 g/mole
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WebNov 23, 2024 · Br2 + 2KI --> 2KBr + I2. Try Cd + HCl. According to the activity series for metals, Cd will react with acid by replacing the hydrogen, so the product CdCl2 forms. WebCl2>Br2>I2. C.③实验试管中会生成红色沉淀 ... Cl2,A项正确;实验②可证明Cl2的氧化性大于Br2,若Cl2过量,Cl2与Br2同时遇到KI溶液,Cl2先和KI溶液反应,无法证明Br2的氧化性大于I2,B项不正确;实验③溶液变成红色,不是沉淀,C项不正确;实验④操作不正 … doc pop\\u0027s 52 weeks of active parenting
Solved Identify the reactant that is oxidized and the Chegg.com
WebApr 13, 2024 · See the explanationion below: Explanation: Cl2 + 2KBr → 2KCl + Br2 Given: 300g of Cl2 300g of KBr (a) Mass of Cl2 = 300g Molecular mass of Cl2 = 2 (35.45) = 70.906 g /mol No.of moles of Cl2 = mass/molarmass = 300/70.906 = 4.23 moles Mass of KBr = 300g Molar mass of KBr = 39+ 79.9 = 118.9g/mol No.of moles of KBr = 300/118.9 = 2.52 … WebNov 13, 2012 · Br2 + 2KI --> 2KBr + I2 Bromine oxidizes iodide to iodine and is left as bromide. WebSep 6, 2024 · In this video we determine the type of chemical reaction for the equation KI + Br2 = KBr + I2 (Potassium iodide + Bromine gas). Since we have a metal replacing … doc phil shows